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Subject: | Re: FLASH: Algebra Question |
From: | Wil Roboly/Big Orbit |
Date: | Fri, 5 May 2000 17:59:15 +0100 |
Thank You... :)
> From: "Glen Rhodes" <grhodesdceg [dot] com>
> Reply-To: flasherchinwag [dot] com
> Date: Fri, 5 May 2000 12:34:12 -0500
> To: <flasherchinwag [dot] com>
> Subject: RE: FLASH: Algebra Question
>
> sin Theta = (y2 - y1)
> ----------------------------
> sqrt( (y2-y1)^2 + (x2-x1)^2 )
>
> Then.. take the arcsin of that.. that's your angle.
>
> That's just length of the Y side over the length of the distance
> (hypotenuse) between the points.
>
> ------------------
> Glen Rhodes
> dot com Entertainment Group Inc.
> Tel: (905) 337-8524 x224
> Fax: (905) 337-8630
> www.dceg.com
>
> -----Original Message-----
> From: ownerchinwag [dot] com [ownerchinwag [dot] com]On">mailto:ownerchinwag [dot] com]On Behalf Of Wil
> Roboly/Big Orbit
> Sent: Friday, May 05, 2000 2:19 PM
> To: flasherchinwag [dot] com
> Subject: FLASH: Algebra Question
>
>
> For anyone out there who can figure this out, you'll get a big sweet
> lollipop.
>
> If I have two points P(x1,y1) Q(x2,y2) in 2-space, where P is my origin, how
> do I find the angle theta created by the vector |PQ|? What would be easier,
> to get theta in degrees or find the Arc in Rads?
>
> Wilco
>
>
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Replies
RE: FLASH: Algebra Question, Glen Rhodes
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